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  1. #include <iostream>
  2. #include <cmath>
  3.  
  4. using namespace std;
  5.  
  6. void rozwiazRownanie(double a, double b, double c)
  7. {
  8.     double delta = b * b - 4 * a * c;
  9.  
  10.     cout << "a = " << a << ", b = " << b << ", c = " << c << endl;
  11.     cout << "Delta = " << delta << endl;
  12.  
  13.     if (delta > 0)
  14.     {
  15.         double x1 = (-b - sqrt(delta)) / (2 * a);
  16.         double x2 = (-b + sqrt(delta)) / (2 * a);
  17.         cout << "Dwa pierwiastki rzeczywiste:" << endl;
  18.         cout << "x1 = " << x1 << endl;
  19.         cout << "x2 = " << x2 << endl;
  20.     }
  21.     else if (delta == 0)
  22.     {
  23.         double x = -b / (2 * a);
  24.         cout << "Jeden pierwiastek rzeczywisty:" << endl;
  25.         cout << "x = " << x << endl;
  26.     }
  27.     else
  28.     {
  29.         cout << "Brak pierwiastków rzeczywistych." << endl;
  30.     }
  31.  
  32.     cout << "-----------------------------" << endl;
  33. }
  34.  
  35. int main()
  36. {
  37.     // 1) a = 3, b = 4, c = 5
  38.     rozwiazRownanie(3, 4, 5);
  39.  
  40.     // 2) a = 1, b = 10000, c = 1
  41.     rozwiazRownanie(1, 10000, 1);
  42.  
  43.     return 0;
  44. }
  45.  
Success #stdin #stdout 0s 5312KB
comments (?)
stdin 
Standard input is empty
stdout 
a = 3, b = 4, c = 5
Delta = -44
Brak pierwiastków rzeczywistych.
-----------------------------
a = 1, b = 10000, c = 1
Delta = 1e+08
Dwa pierwiastki rzeczywiste:
x1 = -10000
x2 = -0.0001
-----------------------------
https://ideone.com/YJuLc8
language:
C++ (gcc 8.3)
created:
12 hours ago
visibility:
public

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